Abdul rafay on Nearpeer MDCAT Common Room
Electric field strength at a point between oppositely charged plates isE. If the distance between plates is reduced to half, what will be the new value of electric intensity? • 4E • E/2 • E/4 • 2E
usman · 2026-08-20T18:04:32.879Z
2E because E = delta v/delta r or simply e=v/d
Amna Shahzad · 2026-08-20T18:22:38.004Z
2E




Anzalna · 2026-08-20T18:02:49.913Z
E/2