Muhammad Hassan Imran on Nearpeer MDCAT Common Room
ngular displacement is a scalar quantity because it: A Has no direction B Has magnitude only C Is measured in degrees D Is independent of radius
Sameer Ahmad · 2026-06-29T04:19:43.262Z
Has magnitude only ....like 30°,2πradian, revolution...
Sadia Haram · 2026-06-29T04:34:04.448Z
But the thing is that k yahan mention nh ha na k for which angle qs is quite incomplete....bcz we know k angle small to vector ho ga and have direction as well along the axis of rotation pa iski direction b to dekehty hm
Sadia Haram · 2026-06-29T04:36:10.541Z
And where you were being from quite a long time ?? No updates about flp's as well
Sadia Haram · 2026-06-29T04:39:48.612Z
Correct formula is. s= r theta Where s is the arc length and r is the radius. Because it is the ratio of two lengths, the radius cancels out conceptually when describing the rotation of a rigid body. For any spinning object (like a fan blade or a wheel), a particle close to the center and a particle on the outer edge will both rotate through the exact same angle \theta in a given time, making angular displacement completely independent of the radius.
Sadia Haram · 2026-06-29T04:40:35.124Z
I'll go with option D
Sameer Ahmad · 2026-06-29T04:45:34.014Z
No ,it will consider wrong bcz even if rigid body at minor level the part away from axis will cover more displacement,so it's dependent...D is eliminated ...
Sameer Ahmad · 2026-06-29T04:42:51.325Z
It's MCQ not long question... we need to choose more likely answer.
Sadia Haram · 2026-06-29T05:11:03.987Z
But hm sirf magnitude b nh choose kr skty bcz we know it has direction as well ❤️🩹
Sadia Haram · 2026-06-29T05:11:24.430Z
Sadia Haram · 2026-06-29T04:04:43.400Z
angular displacement both as vector and scaler krta work ...for small angles it act as vector and for large angles it works as scaler .....so it will depend on the given condition