mahnoorkhalidmk1234 · 2026-06-06T20:46:59.975Z

Dekhain, initial state main hamaray pas sin 90° tha, or agar hum formula main is ko put karain to yeh ay ga Fi= ILBsin90° Fi= ILB Kiyun sin 90°, 1 k equal hota hai Ab agar hum second Yan final karain jo k condition batai gayi hai question main to, hamaray do Kaam huay hain, aik current 2/3 reduce hua hai or dosra conductor rotate kiya hai, ab yeh hum per depend karta hai k hum us ko kis side per consider kartay, clockwise Yan anti clockwise, agar wo clockwise move karta hai to, conductor initially 90° per tha to 90+90=180°, or agar anti clockwise move karta hai to tab, 90-90=0°. Ab agar dono ka sin nikala jay to zero k equal hi ain gay, Yani formula main agar hum put karain,to F'= 2/3ILB sin 180° F'= zero Or, if we put 0°, the answer remains the same which is zero. Hope this helps.

Sameen · 2026-06-06T21:18:39.791Z

in simple i think that k Agar current ko kam kar ke (\(\frac{2}{3}\)) kiya gaya hai, lekin jab angle 0° ho jaye toh force lagna band ho jati hai. Zero se multiply hone ki wajah se puri magnetic force zero ho jaye gi.