Munazza Faisal Shahzad on Nearpeer MDCAT Common Room
If pressure is doubled while volume change remains constant, work done will: A Become half B Remain same C Double D Become zero Solution Explanation: Since W = P?V, doubling pressure doubles work. Why other options are wrong: � A) Opposite effect � B) Work depends on pressure � D) Incorrect conclusion Anybody explain it bcz age constant volume so no change in volume so V=0 so W=0 but and is double how?
Munazza Faisal Shahzad · 2026-05-26T20:03:20.422Z
But you also said that ∆V =0 and W=P∆V so if ∆V is zero so W will also zero na
Kashaf Naz · 2026-05-26T18:57:57.413Z
This could be explained in a way as we know that pressure and volume have inverse relation so if P is doubled then V must be halved to keep the work constant (or to keep ∆W = zero) but in the scenerio given in the statement only pressure is allowed to be doubled while not allowed the volume to be changed (∆V=0) so if V does not change then doubling the pressure will simply double the work