Ayesha Shakeel on Nearpeer MDCAT Common Room
The de-Broglie wavelength of an electron in the first Bohr orbit is A Equal to one fourth the circumference of the first orbit B Equal to half the circumference of the first orbit C Equal to twice the circumference of the first orbit D Equal to the circumference of the first orbit ya bata dain kaisy ho ga solve
Saba Baloch · 2026-04-30T13:19:19.320Z
Solution is
Saba Baloch · 2026-04-30T13:23:53.607Z
Mvr =nh/2π for 1st orbit n=1 then mvr=h/2π by changing the equation 2πr=h/mvr where's 2πr= circumference of the circle and h/mvr= de Broglie wavelength so by comparing both we get de Broglie wavelength=circumference of circle
Ayesha Shakeel · 2026-04-30T14:41:56.662Z
jazakillah
Ali Farooqi · 2026-04-30T13:42:40.960Z
2nd postulate of Bohr model..... mvr=nh/2Pi..... D is best
Saba Baloch · 2026-04-30T13:19:10.780Z
Option d is correct